A rectangular wire frame with one movable side is covered by a soap film (fig.). What work (erg) will be done if this side of the frame is moved a distance S = 2 mm? The length of the movable side is λ = 6cm. The surface tension of the soap film is α = 40 dyn/cm.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(96)
Sol. F = 2T λ = 2 × 40 × 6 = 480 dyne
W = F x = 480 × 0.2 = 96 erg
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